(I) Since R is mapping A to B. Then R must be of the form;
"R=\\{(a,b): a\\in A, b\\in B\\}"
But, the first element of R, (v,z) does not obeya this rule. Thus R is not a relation. Hence it's neither injective nor surjective and has no inverse.
(II) Since for every "a, b\\in A, ~~ R(a)=R(b)\\implies a=b\\\\\n\\text{Thus, } R \\text{ is injective}\\\\\n\\text{Also, every element of B is used up in the relation. Thus, } R \\text{ is surjective.}\\\\\n\\text{The inverse of R is}\\\\\nR^{-1}=\\{(2,1), (3,2), (4,3), (5,4), (1,5)\\}."
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