See the given Venn diagram for notations.
L+N+O=27-H-(M+K+F+G)=27-20-7=0. Therefore, "L=N=O=0".
If the values of K and M are given, we can calculate all the others:
E=2-K (since 2 take tea, coffee and chocolate);
D=12-(E+K)-N=12-2-0=10 (since 12 take tea and coffee);
F=3-K (since 3 take chocolate, tea and cocoa);
C=9-(E+F+K)=9-(2-K)-(3-K)-K=4+K (since 9 take tea and chocolate);
G=7-(K+F)-M=7-3-M=4-M (since 7 take chocolate and cocoa);
J=60-I-(D+E+K+N)-O-M=60-30-12-0-M=18-M
N+L=36-A-D-(C+E+F+K)=36-17-10-9=0. Therefore, "L=N=0" again.
Calculate for now, how many students take chocolate:
B+G+(C+F+K+E)+J+M=47+(4-M)+9+(18-M)+M=78-M
where M can take the values 0, 1, 2, 3 or 4.
How many students take Fanta? We have no data on this question.
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