Question #216254

Suppose U = {1, 2, 3, 4, 5, a, b, c} is a universal set with the subset A = {a, b, c, 1, 2, 3, 4}. Answer questions 1 and 2 by using the given sets U and A. 

Question 1 Which one of the following relations on A is NOT functional?

 1. {(1, 3), (b, 3), (1, 4), (b, 2), (c, 2)}

2. {(a, c), (b, c), (c, b), (1, 3), (2, 3), (3, a)}

3. {(a, a), (c, c), (2, 2), (3, 3), (4, 4)}

4. {(a, c), (b, c), (1, 3), (3, 3)} 

Question 2

Which one of the following alternatives represents a surjective function from U to A? 

1. {(1, 4), (2, b), (3, 3), (4, 3), (5, a), (a, c), (b, 1), (c, b)}

2. {(a, 1), (b, 2), (c, a), (1, 4), (2, b), (3, 3), (4, c)}

3. {(1, a), (2, c), (3, b), (4, 1), (a, c), (b, 2), (c, 3)}

4. {(1, a), (2, b), (3, 4), (4, 3), (5, c), (a, a), (b, 1), (c, 2)} 


1
Expert's answer
2021-07-12T17:57:45-0400

Question 1


Since the relation {(1,3),(b,3),(1,4),(b,2),(c,2)}\{(1, 3), (b, 3), (1, 4), (b, 2), (c, 2)\} contains two different pairs (1,3) and (1,4) with the same first coordinate, we conclude that this relation is not functional. In the rest cases there are no pairs with the same first soordinate, and hence all these relations are functional.


Answer: 1


Question 2


1. Since range{(1,4),(2,b),(3,3),(4,3),(5,a),(a,c),(b,1),(c,b)}={4,b,3,a,c,1,b}A,range \{(1, 4), (2, b), (3, 3), (4, 3), (5, a), (a, c), (b, 1), (c, b)\}=\{4,b,3,a,c,1,b\}\ne A,

we conclude that this function is not surjective.


2. Since range{(a,1),(b,2),(c,a),(1,4),(2,b),(3,3),(4,c)}={1,2,a,4,b,3,c}=A,range \{(a, 1), (b, 2), (c, a), (1, 4), (2, b), (3, 3), (4, c)\}=\{1,2,a,4,b,3,c\}= A, but domain{(a,1),(b,2),(c,a),(1,4),(2,b),(3,3),(4,c)}={a,b,c,1,2,3,4}Udomain \{(a, 1), (b, 2), (c, a), (1, 4), (2, b), (3, 3), (4, c)\}=\{a,b,c,1,2,3,4\}\ne U we conclude that this is not a surjective function from UU to AA.


3. Since range{(1,a),(2,c),(3,b),(4,1),(a,c),(b,2),(c,3)}={a,c,b,1,2,3}A,range \{(1, a), (2, c), (3, b), (4, 1), (a, c), (b, 2), (c, 3)\}=\{a,c,b,1,2,3\}\ne A, we conclude that this function is not surjective.


4. Since range{(1,a),(2,b),(3,4),(4,3),(5,c),(a,a),(b,1),(c,2)}={a,b,4,3,c,a,1,2}=Arange \{(1, a), (2, b), (3, 4), (4, 3), (5, c), (a, a), (b, 1), (c, 2)\}=\{a,b,4,3,c,a,1,2\}= A and domain{(1,a),(2,b),(3,4),(4,3),(5,c),(a,a),(b,1),(c,2)}={1,2,3,4,5,a,b,c}=U,domain \{(1, a), (2, b), (3, 4), (4, 3), (5, c), (a, a), (b, 1), (c, 2)\}=\{1,2,3,4,5,a,b,c\}=U, we conclude that this function is surjective function from UU to AA .


Answer: 4



Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS