Solution:
R1={(a,b)∣a=b} 
So, {(a,a)}∈R1 , thus it is reflexive relation.
Next, 
(a,b)∈R1⇒(b,a)∈R1∵a=b⇒(a,a)∈R1⇒(a,a)∈R1 
thus it is symmetric relation.
Further,
(a,b)∈R1,(b,c)∈R1⇒(a,c)∈R1∵a=b⇒b=c,a=c⇒(a,a)∈R1,(a,a)∈R1⇒(a,a)∈R1 
thus it is transitive relation.
Hence, it is an equivalence relation.
                             
Comments