Solution:
R1={(a,b)∣a=b}
So, {(a,a)}∈R1 , thus it is reflexive relation.
Next,
(a,b)∈R1⇒(b,a)∈R1∵a=b⇒(a,a)∈R1⇒(a,a)∈R1
thus it is symmetric relation.
Further,
(a,b)∈R1,(b,c)∈R1⇒(a,c)∈R1∵a=b⇒b=c,a=c⇒(a,a)∈R1,(a,a)∈R1⇒(a,a)∈R1
thus it is transitive relation.
Hence, it is an equivalence relation.
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