cnf of q^(-q->(p^(-p->r)))
Given expression is-
q∧( q=>(p∧( p=>r)))q \land (~q =>(p \land (~p=>r)))q∧( q=>(p∧( p=>r)))
Whenever we have to write the cnf of the given expression, There is a simple change like the ′∧′'\land'′∧′ is replaced by ′∨′'\lor'′∨′ and ′∧′'\land'′∧′ is replaced by ′∨′.'\lor'.′∨′.
So
CNF is q ∨\lor∨ (~q=>(p ∨\lor∨ (~p=>r)))
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