In a class of 16 students, there are 6 male students and 10 female students. In how many ways can you select a group of 5 students from this class such that 3 of the 5 students are males and the other two are females?
3 male students we can select by "C_6^3 = \\frac{{6!}}{{3!(6 - 3)!}} = \\frac{{6!}}{{3!3!}} = \\frac{{4 \\cdot 5 \\cdot 6}}{6} = 20" ways.
Other 2 female students we can select by "C_{10}^2 = \\frac{{10!}}{{2!(10 - 2)!}} = \\frac{{10!}}{{2!8!}} = \\frac{{9 \\cdot 10}}{2} = 45" ways.
then the total number of ways is 20*45=900.
answer: 900 ways
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