the number of combinations of five objects taken two at a time is?
One would assume for your question that the order in which these objects are picked is irrelevant. Therefore, we can use a function from combinatorics called the combination, where the number of combinations choosing p objects from a set of n objects is equal to ncq=n!/((n−q)!q!). In this case, that would be equal to
(5!)/((5−2)!2!)
=120/(3!2!)
=120/(6*2)
10
Therefore there are 10 combinations of 5 objects taken two at a time.
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