2(i) There are n elements in the set and binary operation i.e 2 operations can be applied on each of them in relation hence the total number of combinations will be "2^n . 2^{n-1} ... 2^2 . 2 = 2^{1+2+...n} = 2^{\\frac{n(n-1)}{2}}" .
(ii) i. How many binary operations can be defined on a set with 4 elements?
The formula is "2^{n(n-1)\/2}" where n is number of elements as explained in 2(i).
Hence So, Binary operations can be defined on a set with 4 elements "= 2^{4(4-1)\/2} = 2^6 = 64" .
3) On the Rubik's Cube, there are 54 facets that can be arranged and rearranged through
twisting and turning the faces. Any position of the cube can be describe as a permutation from the solved state. Thus, the Rubik's Cube group is a subgroup of a permutation
group of 54 elements.
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