A={1,2,3,5,5}
RELATION shows in matrix form
"\\begin{bmatrix}\n 1& 1 & 1 & 1 & 1 \\\\\n 0 & 1 & 1 & 1 & 1\\\\\n 0 & 0& 1& 1 &1\\\\\n 0 & 0& 0 & 1&1\\\\\n 0&0&0&0&1\\\\\n\n\\end{bmatrix}"
Reflexive:all diagonal elements be 1
Transitivity: aRb and bRc then aRc
Matrix shows transitivity
Relation ton="\\begin{bmatrix}\n 1& 1& 1&1&1\\\\\n 0&1&0&1&0\\\\\n 0&0&1&0&0\\\\\n 0&0&0&1&0\\\\\n 0&0&0&0&1\\\\\n\\end{bmatrix}"
Matrix shows reflexive all diagonal elements be 1
Antisymmetric shows : i Relate to j then j not relate to y
Comments
Dear mofa, the matrix T in the solution is called the matrix Relation ton, the arrow diagram also was shown.
this answer was not in detail you are not make the relation of R as well as ton
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