Question #82783

Uxx +Uyy = Q(x,y)
U= C (constant)
this is possions equation ..u are requested to solve it by splitting the problem into two parts.
u=v+w
v----> non-homogeneous equation with homogeneous boundary conditions
w----> homogeneous equation with non homogeneous boundary condition
1

Expert's answer

2018-11-12T11:20:09-0500

Answer on Question # 82783, Math / Differential Equations

Question 1. Let uxx+uyy=Q(x,y)u_{xx} + u_{yy} = Q(x,y) and u(x,y)=cu(x,y) = c. Assume u=v+wu = v + w, where vv \to nonhomogeneous equation with homogeneous boundary conditions, ww \to homogeneous equation with non homogeneous boundary condition.

Solution. Let Δu(x,y)uxx(x,y)+uyy(x,y)=Q(x,y)\Delta u(x,y) \equiv u_{xx}(x,y) + u_{yy}(x,y) = Q(x,y), (x,y)Ω(x,y) \in \Omega, where Ω\Omega is some region in the plane. If Q(x,y)0Q(x,y) \neq 0 this equation is called the Poisson equation.

Let u=v+wu = v + w where Δv(x,y)=f(x,y)\Delta v(x,y) = f(x,y), (x,y)Ω(x,y) \in \Omega and Bv(x,y)=0Bv(x,y) = 0, (x,y)Ω(x,y) \in \partial \Omega; Δw(x,y)=0\Delta w(x,y) = 0, (x,y)Ω(x,y) \in \Omega and Bw(x,y)=g(x,y)Bw(x,y) = g(x,y), (x,y)Ω(x,y) \in \partial \Omega. General form for boundary condition:


Bu(x,y)α(x,y)un(x,y)+β(x,y)u(x,y)=g(x,y),(x,y)Ω.B u (x, y) \equiv \alpha (x, y) \frac {\partial u}{\partial n} (x, y) + \beta (x, y) u (x, y) = g (x, y), (x, y) \in \partial \Omega .


We have Dirichlet boundary condition: Bu(x,y)=u(x,y)=cBu(x,y) = u(x,y) = c.

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