Answer to Question #79058 in Differential Equations for prromise ayansola

Question

Solve the initial value problem y′−2xy=1,y(0)=y0
y=e^−x2 (∫x0 e^−t2 dt+y0)
y=e^x2 (∫x0 e^−t2 dt+y0)
y=e^x2 (∫x0 e^t2 dt-y0)
y=(∫x0 e^−t2 dt+y0)