Answer to Question #59047 in Differential Equations for ABJ

Question

8 Solve: y(xy+1) dx + x(1+xy+x^2y^2) dy=0
(a) 2x^2y^2lny − 2xy −1=Cx^2y^2
(b) 3x^2y^2 lny − 2xy −3=Cx^2y^2
© 2x^2y^2 lny − xy=Cx^2y^2
(d) 2x^3y^2lny −2xy −1=Cx^2y^5
9 Solve
Xdy – ydx –√ x^2−y^2 dx = 0
(a) Cx = 2e^arcsiny/x
(b) Cx = e^arcsiny/x
© Cx = e^arcsin2y/3x
(d) Cx = e^arccosy/x
10 The population of student P at NOUN increases at a rate proportional to the population and to the addition of 150,250 and the population divided by 3, the differential equation of this statement is
(a) dP/dT=3 kP(150,250+P)/4
(b) dP/dT = 2kP(150,250+P)/3
© 5 dP/dT = kP(150,250+P)/3
(d) dP/dT=kP(150,250+P)/3