Answer to Question #59041 in Differential Equations for ABJ

Question

5 Solve the variable separable x^3dx+(y+1)^2dy=0
(a) 3x^4+4(y+2)^3=C
(b) 5x^4+4(y+1)^3=C
© 3x^4+4(y+1)^3=C
(d) 4x^4+4(y+2)^3=C
6 Solve : (x^3+y^3)dx−3xy^2dy=0
(a) x^5−2y^3=Cx
(b) x^3−2y^3=Cx
© x^3−3y^3=Cx
(d) x^3−2y^2=Cx
7 Solve : (1+2e^x/y)dx+2e^x/y(1− x/y)dy=0
(a) 5x+2ye^x/y=C
(b) x+2ye^2x/y=C
© x+2ye^x/y=C
(d) 5x+3ye^x/y=C