Answer to Question #58204 in Differential Equations for Nayan Jyoti Das
1. a) Solve the following ordinary differential equations:
i) 1/x sin ydx + [(ln x)(cos y) + y)] dy = 0
ii) d^2 y / dx^2 + dy/dx - 12y = 4e^2x
b) Solve the initial value problem:
d^2 y / dx^2 + 2(dy/dx) + 2y=0, y(0)=2, y'(0)=1
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2016-03-09T08:36:42-0500
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