Let's find y′ and y′′ :
y=Ax+Bx2
y′=A+2Bx (1)
y′′=2B (2)
From (2) we have:
B=2y′′
Putting B into (1) we obtain:
y′=A+22y′′x=A+y′′x
A=y′−y′′x
Substituting A and B into the origin equation we get:
y=(y′−y′′x)x+2y′′x2
2x2y′′−xy′+y=0
Answer: 2x2y′′−xy′+y=0 .
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