Form a partial differential equation by eliminating the function f from z = f(y/x)
Given, "z = f\\left(\\dfrac{y}{x}\\right)".
Differentiating partially with respect to "x", we get
"p=\\dfrac{\\partial z}{ \\partial x}=f'\\left(\\dfrac{y}{x}\\right)\\cdot \\dfrac{-y}{x^2}\\\\ \\\\\n\n\\therefore~f'\\left(\\dfrac{y}{x}\\right)= -\\dfrac{px^2}{y} \\qquad\\qquad~~~~~(1)"
Differentiating partially with respect to "y", we get
"q=\\dfrac{\\partial z}{ \\partial y}=f'\\left(\\dfrac{y}{x}\\right)\\cdot \\dfrac{1}{x}\\\\\nf'\\left(\\dfrac{y}{x}\\right) = qx \\qquad\\qquad\\qquad~~~~~~~~(2)"
From (1) and (2), we get
"\\begin{aligned}\n-\\dfrac{px^2}{y} &= qx\\\\\n-px &= qy\\\\\nxp + yq &= 0\n\\end{aligned}"
which is the required partial differential equation.
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