Q2. (c) Find the general solution of the first-order linear partial differential equation xux + yuy = u and investigate first-order, quasi-linear and linear partial differential equations.
We have the linear differential equation
"xu_x+yu_y=u"
The system of eqautions is,
"\\dfrac{dx}{x}=\\dfrac{dy}{y}=\\dfrac{du}{u}"
Now, taking first two terms
"\\dfrac{dx}{x}=\\dfrac{dy}{y}"
Integrating Both the sides-
"\\text{lnx}=\\text{lny}+C_1\\\\\n\n\\text{lnx}-\\text{lny}=\\text{ln}e^{C1}"
"(\\dfrac{x}{y})=e^{C1}\\\\\n\n\\dfrac{x}{y}=C1'\\\\\n\n\\phi=\\dfrac{x}{y}=C1'"
Now, taking last two terms
"\\Rightarrow\\dfrac{dy}{y}=\\dfrac{du}{u}\\\\\\Rightarrow\n\nlny=lnu+C_2\\\\\n\n\\Rightarrow lny=lnu+lne^{C_2}\\\\\\\\\n\n\\Rightarrow ln(\\dfrac{y}{u})=lne^{C_2}"
"\\Rightarrow \\dfrac{y}{u}=e^{C2}"
"\\Rightarrow \\dfrac{y}{u}=C_2'"
"\\Rightarrow\\epsilon=\\dfrac{y}{u}=C_2'"
Hence, the general solution is "f(\\phi,\\epsilon)=f(\\dfrac{x}{y},\\dfrac{y}{u})=0"
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Dear Opeyemi Yahaya, please use the panel for submitting a new question.
Solve (d²u)/(dxdt) = sin(x+t) at t=0, ux=1 and at x=0, x=(1-t)²
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