Integral on Curve [ e ^ (z+1) ] / [ (z-i) ( z^2 + (i-1)z-i)^3 ]
Note : 1))please the figure is close curve I cannot paint it by writing but these points (3i,i,-i,-2i,-1) inside the figure if you need it when find the singularity inside the curve
2))Also I need all singularity ( then sure only if inside curve i need all one with the working of cauchy integral , then plus it to find the total integral
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Dear Alyaa. You initially posted the problem different from the one
proposed in this comment. Though we made changes to the solution.
Alyaa
06.01.15, 18:13
Dears Thanks for answered but i have comment on my paid question I
appreciate your reply ASAP A- Use cauchy integral formula to evaluate
[e^{z+1} ] right but divide by / [(z-i). {(z^2 + (i-1)z-i)}^3; (z-i)
it the different not ^ 3 (not power three).So should [e^{z+1} ] / [
(z-i). {(z^2 + (i-1)z-i)}^3] B- the singularity 1 not include the
curve ,so only i and -i C- the cuachy formula per each singality = {
[2.pi.i] / [n!] } .{f^n} (at singularity ) , not [n!] / [2.pi.i] . f^n
(at singularit
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Dear Alyaa. You initially posted the problem different from the one proposed in this comment. Though we made changes to the solution.
Dears Thanks for answered but i have comment on my paid question I appreciate your reply ASAP A- Use cauchy integral formula to evaluate [e^{z+1} ] right but divide by / [(z-i). {(z^2 + (i-1)z-i)}^3; (z-i) it the different not ^ 3 (not power three).So should [e^{z+1} ] / [ (z-i). {(z^2 + (i-1)z-i)}^3] B- the singularity 1 not include the curve ,so only i and -i C- the cuachy formula per each singality = { [2.pi.i] / [n!] } .{f^n} (at singularity ) , not [n!] / [2.pi.i] . f^n (at singularit
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