All the cube roots of I in C are z₁ = cos(π/2)+ i sin(π/2) , z₂ = cos (π/6)+ isin(π/6) and z₃ = cos (5π/6)+i sin (5π/6)
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Expert's answer
2021-08-29T16:40:55-0400
The polar form of i is 1(cos(2π)+isin(2π)).
According to the De Moivre's Formula, all cubic roots of a complex number 1(cos(2π)+isin(2π)) are given by 11/3(cos(3π/2+2πk)+isin(3π/2+2πk)),k=0,1,2.
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