Let n=7x+4,x=0,1,2,... and let m=9y+7,y=0,1,2,... Then
n×m=(7x+4)(9y+7)=63xy+49x+36y+28 y=0, if n×m is divided by 7 the remainder is 0.
126÷7=18
m=9(0)+7=7,n=7(2)+4=18
y=1, if n×m is divided by 7 the remainder is 1.
22÷7=3,remainder 1
m=9(1)+7=16 But 22 is not divisible by 16.
y=2, if n×m is divided by 7 the remainder is 2.
44÷7=6,remainder 2
m=9(2)+7=25 But 44 is not divisible by 25.
y=3, if n×m is divided by 7 the remainder is 3.
24÷7=2,remainder 3
m=9(3)+7=34 But 24 is not divisible by 34.
y=4, if n×m is divided by 7 the remainder is 4.
44÷7=6,remainder 2
m=9(2)+7=25 But 44 is not divisible by 25.
55÷7=7,remainder 6 y=6, if n×m is divided by 7 the remainder is 6.
m=9(6)+7=61 But 55 is not divisible by 61.
(D) 126
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