1. Subtract the binary numbers 11102 from 101012
Let us subtract the binary numbers 11102 from 101012:
101012 11102−−− 111210101_2\\ \ \ 1110_2\\ ---\\ \ \ \ \ 111_2101012 11102−−− 1112
Let us verify using decimal system:
101012=1⋅24+0⋅23+1⋅22+0⋅2+1=16+4+1=211011102=1⋅23+1⋅22+1⋅2+0=8+4+2=14101112=1⋅22+1⋅2+1=4+2+1=71010101_2=1\cdot 2^4+0\cdot 2^3+1\cdot 2^2+0\cdot 2+1=16+4+1=21_{10} \\ 1110_2=1\cdot 2^3+1\cdot 2^2+1\cdot 2+0=8+4+2=14_{10}\\ 111_2=1\cdot 2^2+1\cdot 2+1=4+2+1=7_{10}101012=1⋅24+0⋅23+1⋅22+0⋅2+1=16+4+1=211011102=1⋅23+1⋅22+1⋅2+0=8+4+2=14101112=1⋅22+1⋅2+1=4+2+1=710
And 14+7=2114+7=2114+7=21
Answer: 1112
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