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[SADT3] For scalar functions u and v, show that



B=( nabla u)*( nabla v)



is solenoidal and that



A= 1 2 (u nabla v-v nabla u)



is a vector potential for B, i.e. B= nabla* A

The Laplacian of a function f

 of n

 variables x

1

,x

2

,⋯x

n

, denoted ∇

2

f

 is defined by


2

f(x

1

,x

2

,⋯,x

n

):=∂

2

f

∂x

2

1


+∂

2

f

∂x

2

2


+⋯+∂

2

f

∂x

2

n


Now assume that f

 depends only on r

 where r=(x

2

1

+x

2

2

+⋯+x

2

n

)

1

2


, i.e. f(x

1

,x

2

,⋯,x

n

)=g(r)

, for some function g

. Show that, for x

1

,x

2

,⋯,x

n

≠0

,


2

f=n−1

r


g

(r)+g

′′

(r)



 If A

 and B

 are vector fields, prove the following:


∇(AB)=(B⋅∇)A+(A⋅∇)B+B×(∇×A)+A×(∇×B).

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  1. D2((x+1)2/x-1)            ans, 8/(x-1)3
  2. D(ln(x2-2x+1))            ans, 2/x-1
  1. D(x2+2x-3)                  ans, 2x+2
  2. D2(xe3x-e4x)                 ans, 9xe3x+633x-16e4x

 Use Monte Carlo integration to estimate the integral of a function. Also calculate the error-> limit(1,0) ∫ 𝑥 ^2 (3𝑥 + 1)𝑑x

Evaluate the following functions in differential operator form.

  1. D2((x+1)2/x-1) Answer: 8/(x-1)3
  2. D(ln(x2+2x+1) Answer: 2/x-1

A manufacturer packages his product in a 500-ml cylindrical can. The material for the

top costs four times as much per square centimeter as that to be used for the bottom and

the sides. What must be its dimensions so that the cost of the can is least?


Let S be the closed parabolic bowl consisting of two pieces: S1: z = x2 + y2, x2 + y2 ≤ 1; and S2: x = rCos(ɸ), y = rSin(ɸ), z = 1 for 0≤ɸ≤2π, and 0≤r≤1. Let (the vector) F = (x-y+z)î + 2xĵ + k̂. Compute both sides of Gauss’s Divergence Formula (as given in the class) and show that they are equal.


Find the extreme values of z

 on the surface 2x

2

+3y

2

+z

2

−12xy+4xz=35



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