a right circular cylinder has a fixed height of 6 units. Find the rate of change of its volume V with respect to the radius r of its base. Find the rate of change of the total surface area A with respect to r.
dVdr=d(πr2)hdr=2πrh\frac{dV}{dr}=\frac{d(πr^2)h}{dr}=2πrhdrdV=drd(πr2)h=2πrh
dAdr=d(2πr2+2πrh)dr=4πr+2πh=2π(2r+h)\frac{dA}{dr}=\frac{d(2πr^2+2πrh)}{dr}=4πr+2πh=2π(2r+h)drdA=drd(2πr2+2πrh)=4πr+2πh=2π(2r+h)
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