Answer to Question #76448 in Calculus for BIVEK SAH

Question

Let the function f:R^2-->R is defined as follow
f(x,y)=[xy(x^2-y^2)]/x^2+y^2 if(x,y )not=(0,0)
=0 if (x,y)=(0,0)
Then show that
1)fx(0,y)=y for all y

2)fx(x,0)=x for all x.
So that fxy(0,0)not=fyx(0,0)