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Answer to Question #75837 in Calculus for Nikhil Gupta
Question #75837
Obtain the Fourier series expansion for the following periodic function which has a
period of π: f(x)={(4/π)x for 0<x<π/2 (-4/π)x for (-π/2)<x<0
period of π: f(x)={(4/π)x for 0<x<π/2 (-4/π)x for (-π/2)<x<0
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