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Answer to Question #61376 in Calculus for bebeji
Question #61376
7 Given
2x5+x2−5t2
2x5+x2−5t2
, find
dydx
dydx
by using the first principle
c
−t−2+8t−3
−t−2+8t−3
6t+7t−3
6t+7t−3
t2+5t−3
t2+5t−3
6t2+10t−3
6t2+10t−3
8 Given
y(x)=x4−4x3+3x2−5x
y(x)=x4−4x3+3x2−5x
, evaluate
d4ydx4
d4ydx4
30
42
24
22
2x5+x2−5t2
2x5+x2−5t2
, find
dydx
dydx
by using the first principle
c
−t−2+8t−3
−t−2+8t−3
6t+7t−3
6t+7t−3
t2+5t−3
t2+5t−3
6t2+10t−3
6t2+10t−3
8 Given
y(x)=x4−4x3+3x2−5x
y(x)=x4−4x3+3x2−5x
, evaluate
d4ydx4
d4ydx4
30
42
24
22
Expert's answer
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