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Answer to Question #59505 in Calculus for ???????
Question #59505
The Voltage, v across the plates of the charging capacitor varies with time, t according to the formula;
v = V (1 - e^-(t/T)), where T = CR and is called the time constant
c = 100nF R = 47kOhms and V = 5V
Differentiate the charging equation and find the rate of change of voltage at 6ms
v = V (1 - e^-(t/T)), where T = CR and is called the time constant
c = 100nF R = 47kOhms and V = 5V
Differentiate the charging equation and find the rate of change of voltage at 6ms
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