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Answer to Question #50584 in Calculus for Aaqib Zaman
Question #50584
The length, l mm of an elastic string at time t seconds is given by
l = t^3/3 - 4t + 10
Find the instants (that is, the value of t ) when
a) The length is increasing at a rate of 5 mm/Sec
b) The length is decreasing at a rate of 4 mm/Sec
l = t^3/3 - 4t + 10
Find the instants (that is, the value of t ) when
a) The length is increasing at a rate of 5 mm/Sec
b) The length is decreasing at a rate of 4 mm/Sec
Expert's answer
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