Find the second derivative of the following function:
F(x)=3x^3 − 1 / x + e^2x.
is
a.18x − ln x + 4e^2x
b.18x − 2 / x^3 + 2e^2x
c.18x + 2 / x^3 + 4e^2x
d.18x − 2 / x^3+ 4e^2x
y′=(3x3−1x+e2x)′=9x2+1x2+2e2xy' = {\left( {3{x^3} - \frac{1}{x} + {e^{2x}}} \right)^\prime } = 9{x^2} + \frac{1}{{{x^2}}} + 2{e^{2x}}y′=(3x3−x1+e2x)′=9x2+x21+2e2x
y′′=(9x2+1x2+2e2x)′=18x−2x3+4e2xy'' = {\left( {9{x^2} + \frac{1}{{{x^2}}} + 2{e^{2x}}} \right)^\prime } = 18x - \frac{2}{{{x^3}}} + 4{e^{2x}}y′′=(9x2+x21+2e2x)′=18x−x32+4e2x
Answer: d
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