Find the coordinates of the points on the curve 𝑦 = 3𝑥³ − 2𝑥² − 12𝑥 + 2 where
the normal is parallel to the line 𝑦 =− 𝑥 + 1.
Find the coordinates of the points on the curve 𝑦 = 3𝑥³ − 2𝑥² − 12𝑥 + 2 where
the normal is parallel to the line 𝑦 =− 𝑥 + 1.
The derivative
The slope of the normal is -1, hence the slope of the tangent line is .
Then
The points are
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