Question #295389

Given f(x)=x^7 -x^5 -x^4 +2x +1 on interval [-1,1] show that there's at least one critical point on this interval.


Expert's answer

f(x)=x7−x5−x4+2x+1f(x)=x^7 -x^5 -x^4 +2x +1


The function f(x)f(x) is continuous and differentiable on R\R as polynomial.

f′(x)=7x6−5x4−4x3+2f'(x)=7x^6-5x^4-4x^3+2f′(0)=2>0f'(0)=2>0

f′(0.8)=7(0.8)6−5(0.8)4−4(0.8)3+2f'(0.8)=7(0.8)^6-5(0.8)^4-4(0.8)^3+2

=−0.260992<0=-0.260992<0

Then by the Intermediate Value Theorem, there exists a number c∈(0,0.8)c\in (0, 0.8) such that f′(c)=0.f'(c)=0.

Therefore there's at least one critical point on the interval[−1,1].[-1,1].


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