Answer to Question #295389 in Calculus for DAN

Question #295389

Given f(x)=x^7 -x^5 -x^4 +2x +1 on interval [-1,1] show that there's at least one critical point on this interval.


1
Expert's answer
2022-02-09T17:36:13-0500
f(x)=x7x5x4+2x+1f(x)=x^7 -x^5 -x^4 +2x +1


The function f(x)f(x) is continuous and differentiable on R\R as polynomial.

f(x)=7x65x44x3+2f'(x)=7x^6-5x^4-4x^3+2f(0)=2>0f'(0)=2>0

f(0.8)=7(0.8)65(0.8)44(0.8)3+2f'(0.8)=7(0.8)^6-5(0.8)^4-4(0.8)^3+2

=0.260992<0=-0.260992<0

Then by the Intermediate Value Theorem, there exists a number c(0,0.8)c\in (0, 0.8) such that f(c)=0.f'(c)=0.

Therefore there's at least one critical point on the interval[1,1].[-1,1].


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