decompose g(x)=5/(x−1)3g(x)=5/(x-1)^3g(x)=5/(x−1)3
We are looking for two functions, f and h such that
g(x)=f(h(x))g(x)=f(h(x))g(x)=f(h(x))
Here, g(x)=5(x−1)3g(x)=\frac{5}{(x-1)^3}g(x)=(x−1)35
We can take f(x)=5x3 and h(x)=(x−1)f(x)=\frac{5}{x^3}\ \text{and}\ h(x)=(x-1)f(x)=x35 and h(x)=(x−1) such that g(x)=f(h(x))g(x)=f(h(x))g(x)=f(h(x))=5(x−1)3=\frac{5}{(x-1)^3}=(x−1)35
We could then decompose the function as
f(x)=5x3 and h(x)=(x−1)f(x)=\frac{5}{x^3}\ \text{and}\ h(x)=(x-1)f(x)=x35 and h(x)=(x−1)
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