Question #266111

What is Integration? Discuss types of Integration with Example.


1
Expert's answer
2021-11-15T16:36:01-0500

The integral of a function abf(x)dx\int_a^b{f(x)dx} gives the area under the curve between the limits x=a and x=b.

Integrating refers to the summation of discreet data and is a reverse process of differentiation.

1) integration by parts

This type of integration is applied when integrating between a product of two functions.

Example:

x sec2x dx\int x\ sec^2x\ dx

=xSec2x dx(Sec2x dx)(1dx)=x\int Sec^2 x\ dx-\int (\int Sec^2x\ dx)(1dx)

=x tan xtan xdx=x\ tan \ x-\int tan\ x dx

=x tanx+lncos x+C=x\ tanx +ln|cos\ x|+C


2) integration by partial fractions

This type of integration is applied when the function to be integrated are rational proper fraction in the form P(u)Q(u)\frac{P(u)}{Q(u)}

Example:

2x+3(x3)(x+1)dx\int{\frac{2x+3}{(x-3)(x+1)}dx}

2x+3(x3)(x+1)=Ax3+Bx+1\frac{2x+3}{(x-3)(x+1)}=\frac{A}{x-3}+\frac{B}{x+1}

    2x+3=A(x+1)+B(x3)\implies2x+3=A(x+1)+B(x-3)

A+B=2

A-3B=3

We solve above to get A=94\frac{9}{4} and B=14-\frac{1}{4}

Now 2x+3(x3)(x+1)dx=94x3dx+14x+1dx\int{\frac{2x+3}{(x-3)(x+1)}dx}=\int{\frac{\frac{9}{4}}{x-3}dx}+\int{\frac{-\frac{1}{4}}{x+1}dx}

=94lnx314lnx+1+C=\frac{9}{4}ln|x-3|-\frac{1}{4}ln|x+1|+C


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