1. If the radius of the circle increases at the rate of 0.01 cm per second, find the rate of change of the area when the radius is 3 cm long
Solution.
We know that the area of the circle determine as "S=\u03c0r^2." Also we have "\\frac{dr}{dt}=0.01" cm/sec, because the radius of the circle increases at the rate of 0.01 cm per second.
Find "\\frac{dS}{dt}=2\u03c0r\\frac{dr}{dt}." Such as r=3 cm, then "\\frac{dS}{dt}=2\u03c0\u20223\u20220.01=0.06\u03c0" cm2/sec or 0.1884 cm2/sec.
Answer. 0.1884 cm2/sec
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