Question #232015

state and prove the necessary conditions for the existence of maximum value and minimum value?


1
Expert's answer
2021-09-13T16:35:55-0400

The conditions for a function to be maximum or minimum include if

f(x)=0f’ (x) = 0;

and for maximum f’’(x)f’’ (x) = negative

and for minimum f’’(x)f’’ (x) = positive.



Assume that f:(a,b)Rf: (a,b) \to \R


Theorem:

Let c(a,b)c ∈ (a, b) and f be continuous at c. If for some δ>0,δ > 0, f has a minimum increasing on (cδ,c)(c − δ, c) and decreasing on (c,c+δ),(c,c+δ), then f has a local maximum at c.


Proof:

Choose any x1x_1 and xx such that c δ<x1<x<c.− δ < x1 < x < c. Then f(x1)f(x)f(x_1) ≤ f(x) and by the continuity of ff at cc we have f(x1)limxcf(x)=f(c).f(x_1) ≤ \lim x→c− f(x) = f(c).


Similarly, if c<x2<c+δc < x_2 < c + δ then f(x2)limxc+f(x)=f(c).f(x_2) ≤ \lim x→c+ f(x) = f(c). This proves the result.



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