Answer to Question #194953 in Calculus for Syed Tahmid Shams

Question

Find the volume of the solid generated when the region enclosed by

y = √(x + 3), y = √(2x + 1), x = 0 is revolved about the x-axis.

Answer 1

$\displaystyle \textsf{Point of Intersection:}\\ \sqrt{x + 3} = \sqrt{2x + 1}\\ x + 3 = 2x + 1, x = 3 - 1 = 2\\ \begin{aligned} V &= \pi \int_0^2 (x + 3 - (2x + 1))\,\, \mathrm{d}x \\&= \pi \int_0^2 (2 - x)\,\, \mathrm{d}x \\&= \pi\left(2x - \frac{x^2}{2}\right)\biggr\vert_0^2 \\&= \pi(2) = 2\pi \end{aligned}$