3. Find an interval on which Rolle’s theorem applies to f(x) = x 3 − 7x 2 + 10x. Then, find all the critical points in that interval.
"f(x) = x^ 3 \u2212 7x^ 2 + 10x"
"=x(x^2-7x+10)=x(x-2)(x-5)"
The interval for which The rolles theorem is applicable will be [0,5].
The critical point in that interval can be calculated by putting "f'(x)=0"
"3x^2-14x+10=0\\\\"
"x=\\dfrac{14\\pm \\sqrt{196-120}}{6}=\\dfrac{14\\pm \\sqrt{76}}{6}"
Hence the critical points are "\\dfrac{14- \\sqrt{76}}{6},\\dfrac{14+ \\sqrt{76}}{6}"
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