Find the area of the smaller loop r=2-4sin0, symmetrical with Oy.
We know,
Area can be evaluated as "\\int rd \\theta"
We have given that "r = 2-4sin\\theta"
Hence "I = \\int_{0}^{2\\pi} (2-4sin\\theta) d\\theta"
"I = [_{0}^{2\\pi} (2\\theta+4cos\\theta)"
We get "I = 4\\pi + 4 - 0 - 4"
Hence, "I = 4\\pi"
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