How can we produce the terms of a sequence if the first 10 terms are 1, 2, 2, 3, 3, 3, 4, 4, 4, 4?
the series is like
1,2,2,3,3,3,4,4,4,4...and we have to find 100th position
so to this series 1 is coming at 1st position
2 is repeating until 3rd position
3 is repeating until 6th position
4 until 10 position
from above series it is concluded that
position can be calculated by simply adding no's
now 1+2=3 i.e 2 is repeating until 3rd position
position of 4 can be calculated similarly, 1+2+3+4=10.
now for 100th position
add no's from
1 to 13 which gives 91
which means 13 will repeat until 91 position
from above it is concluded 14 will appear at 100th position
Clearly the ending position of the nth row (EPn)is the sum of all natural numbers upto n =n.(n+1)/2
Means n is 4
4(4+1)/2
=10
So 4 is repeating until 10th position
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