Question #155677

If x= 0 is rational and y irrational, prove that x + y,x − y,xy,x/y and y/x are all irrational.


1
Expert's answer
2021-01-19T04:21:50-0500

Here we have (x0)Q(x\neq0)\in\mathbb{Q} and yQc\in\mathbb{Q}^c


  • x+yx+y

Here let's assume this is rational.

Now, lets take x=3 and y=2\sqrt{2}

So, x+y=3+2x+y=3+\sqrt{2} which is irrational.

So, we have a counter-example to show that x+yx+y is irrational. Hence our claim is false and is irrational.


  • xyx-y

Here let's assume this is rational.

Now, lets take x=3 and y=2\sqrt{2}

So, xy=32x-y=3-\sqrt{2} which is irrational.

So, we have a counter-example to show that xyx-y is irrational. Hence our claim is false and is irrational.


  • xyxy

Here let's assume this is rational.

Now, lets take x=3 and y=2\sqrt{2}

So, xy=32xy=3\sqrt{2} which is irrational.

So, we have a counter-example to show that xyxy is irrational. Hence our claim is false and is irrational.


  • xy\frac{x}{y}

Here let's assume this is rational.

Now, lets take x=3 and y=2\sqrt{2}

So, xy=32\frac{x}{y}=\frac{3}{\sqrt{2}} which is irrational.

So, we have a counter-example to show that xy\frac{x}{y} is irrational. Hence our claim is false and is irrational.


  • yx\frac{y}{x}

Here let's assume this is rational.

Now, lets take x=3 and y=2\sqrt{2}

So, yx=23\frac{y}{x}=\frac{\sqrt{2}}{3} which is irrational.

So, we have a counter-example to show that yx\frac{y}{x} is irrational. Hence our claim is false and is irrational.


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