If x > 0, show that there exists n ∈ N such that 1/n < x.
Here we have "(x\\in\\R)>0" . Which implies "\\frac{1}{x}>0" .
Now, using Archimedean property, we have "n\\in \\N" such that,
Hence, "\\exists n\\in \\N" such that, "x>\\frac{1}{n}"
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