IAs per the given function f(x) = 2x
2 + 10 and g(x) = 4x + 1,
f(x) actually means 4x + 10
In that case f(x) and g(x) represent two parallel straight lines and hence enclose no area.
If f(x) is considered as 2x²+10 and g(x) = 4x + 1 , then no area is bounded by them.
Graph is attached.
But if the function f(x) be considered as f(x) = 2x²+1 and g(x) = 4x+1 then there is a bounded area.
Graph is attached
And area = "\\int_{0}^{2} [g(x) - f(x)] dx"
= "\\int_{0}^{2} [4x + 1 - 2x\u00b2-1] dx"
= "\\int_{0}^{2} [4x - 2x\u00b2] dx"
= [ 4x²/2 - 2x³/3]02
= 8 - 16/3 square unit
= 8/3 square unit
= 2.67 square unit
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