Question #70271

The direction of a vector V(Xv,Yv,Zv) intersects a sphere on point “B”. Assuming O(0,0,0) as the centre and ‘r’ as the radius of the sphere. The mirror of the vector based on OB direction passes the point C(0,0,h). The “B” coordination, B(Xb,Yb,Zb), is required based on the above parameters.

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Answer on Question #70271 – Math – Analytic Geometry

Question

1. The direction of a vector V(XV,YV,ZV)V(X_V, Y_V, Z_V) intersects a sphere on point “BB”. Assuming O(0,0,0)O(0,0,0) as the center and ‘rr’ as the radius of the sphere. The mirror of the vector based on OBOB direction passes the point C(0,0,h)C(0,0,h). The “BB” coordinate, B(XB,YB,ZB)B(X_B, Y_B, Z_B), is required based on the above parameters.

Solution

Vector VV is collinear to the vector OBOB by the definition of a vector. The mirror image of a vector is considered in relation to the same direction. Since the mirror contains a point C(0,0,h)C(0,0,h), the collinear direction of OBOB is OCOC, then the vector VV and its mirror belong to the ZZ-axis.

Therefore, the point of sphere BB belongs to the ZZ-axis, and its coordinates are (0,0,r)(0,0,r) or (0,0,−r)(0,0,-r).

Answer: B(0,0,−r)B(0,0,-r) or B(0,0,r)B(0,0,r).

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