Answer on Question #67860 – Math – Analytic Geometry
Question
Find a unit vector parallel to the resultant vector A1=2i+4j−5k, A2=1+2j+3k
a) 3/7i+6/7j−2/7k
b) 1/7i+63/7j−4/7
c) 2/7i−3/7j−5/7
d) 3/5i+6/5j−2/5
Solution
The resultant vector of A1=2i+4j−5k and A2=i+2j+3k is
A=A1+A2=(2i+4j−5k)+(i+2j+3k)=(2+1)i+(4+2)j+(−5+3)k=3i+6j−2k.
Its length is
∣A∣=9+36+4=7.
A unit vector parallel to the resultant vector is
∣A∣A=73i+76j−72k.
Answer: a) 73i+76j−72k.
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