Question #67860

Find a unit vector parallel to the resultant vector A1=2i+4j−5k, A2=1+2j+3k
a) 3/7i+6/7j−2/7k
b)1/7i+63/7j−4/7
c)2/7i−3/7j−5/7
d)3/5i+6/5j−2/5

Expert's answer

Answer on Question #67860 – Math – Analytic Geometry

Question

Find a unit vector parallel to the resultant vector A1=2i+4j5kA1 = 2i + 4j - 5k, A2=1+2j+3kA2 = 1 + 2j + 3k

a) 3/7i+6/7j2/7k3/7i + 6/7j - 2/7k

b) 1/7i+63/7j4/71/7i + 63/7j - 4/7

c) 2/7i3/7j5/72/7i - 3/7j - 5/7

d) 3/5i+6/5j2/53/5i + 6/5j - 2/5

Solution

The resultant vector of A1=2i+4j5kA_1 = 2i + 4j - 5k and A2=i+2j+3kA_2 = i + 2j + 3k is


A=A1+A2=(2i+4j5k)+(i+2j+3k)=(2+1)i+(4+2)j+(5+3)k=3i+6j2k.A = A_1 + A_2 = (2i + 4j - 5k) + (i + 2j + 3k) = (2 + 1)i + (4 + 2)j + (-5 + 3)k = 3i + 6j - 2k.


Its length is


A=9+36+4=7.|A| = \sqrt{9 + 36 + 4} = 7.


A unit vector parallel to the resultant vector is


AA=37i+67j27k.\frac{A}{|A|} = \frac{3}{7}i + \frac{6}{7}j - \frac{2}{7}k.


Answer: a) 37i+67j27k.\frac{3}{7}i + \frac{6}{7}j - \frac{2}{7}k.

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