Answer to Question #335167 in Analytic Geometry for math

Question #335167

A plane with a velocity 400 km/h, 10 degrees, West of South encounters a wind with a

velocity of 40 km/h, from 35 degrees East of South. What is the plane’s resultant

velocity?


1
Expert's answer
2022-04-29T14:17:06-0400
"\\vec{v}=-400\\sin10\\degree \\vec{i}-400\\cos10\\degree\\vec{j}"

"\\vec{u}=40\\sin35\\degree \\vec{i}-40\\cos35\\degree\\vec{j}"

"\\vec{v}_{res}=\\vec{v}+\\vec{u}"

"=(-400\\sin10\\degree +40\\sin35)\\vec{i}"

"+(-400\\cos10\\degree-40\\cos35\\degree)\\vec{j}"

"\\approx-46.5162\\vec{i}-426.6892\\vec{j}"

"|\\vec{v}_{res}|=\\sqrt{(-46.5162)^2+(-426.6892)^2}"

"\\approx429.2172(km\/h)"

"\\tan \\theta=\\dfrac{-426.6892}{-46.5162}"

"\\theta=264\\degree"

429.217 km/h, 6 degrees, West of South 


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS