A trapezoid has an area of 36 sq. m and an altitude of 2m. Its two bases have ratio of 4:5. Find the perimeter of the trapezoid. Find the percentage increase in the volume if its edge is increased by 1%
"S=36m^2\\\\\nBK=2m\\\\\nBC:AD=4:5"
BK, CM - an altitude
Lets
"BC=4x, AD=5x\\\\\nS=\\frac{BC+AD}{2}\\cdot BK\\\\\nS=\\frac{4x+5x}{2}\\cdot2=36\\\\\n9x=36\\\\\nx=4\\\\\nBC=16m, AD=20m"
"AK=MD=\\frac{AD-BC}{2}=\\frac{20-16}{2}=2(m)\\\\"
"\\triangle ABK, \\angle K=90^0\\\\\nAB^2=AK^2+BK^2\\\\\nAB^2=2^2+2^2=4+4=8\\\\\nAB=\\sqrt{8}=2\\sqrt{2}(m)\\\\\nAB=CD=2\\sqrt{2}m\\\\\nP=AB+BC+CD+AD=\\\\\n=2\\sqrt{2}+16+2\\sqrt{2}+20=36+4\\sqrt{2}(m)"
If AB and CD is increased by 1%=0.01:
"AB'=1.01(2\\sqrt{2})=2.02\\sqrt{2}(m)\\\\\nP'=16+20+2.02\\sqrt{2}+2.02\\sqrt{2}=36+4.04\\sqrt{2}(m)\\\\\n\\frac{P'\\cdot100\\%}{P}=\\frac{(36+4.04\\sqrt{2})\\cdot100\\%}{36+4\\sqrt{2}} \\approx100.14\\%"
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