Question #200598

Use the fact that :

0= x y 1

a1 b1 1

a2 b2 1

to determine the equation of the line passing through the distinct points (a1, b1) and (a2, b2), where |·| stands for det(·), the determinant. 


Expert's answer

∣xy1a1b11a2b21∣=0\begin{vmatrix} x & y & 1 \\ a_1 & b_1 & 1 \\ a_2 & b_2 & 1 \end{vmatrix}=0

x∣b11b21∣−y∣a11a21∣+1∣a1b1a2b2∣=0x\begin{vmatrix} b_1& 1 \\ b_2 & 1 \end{vmatrix}-y\begin{vmatrix} a_1 & 1 \\ a_2 & 1 \end{vmatrix}+1\begin{vmatrix} a_1 & b_1 \\ a_2 & b_2 \end{vmatrix}=0

x(b1−b2)−y(a1−a2)+a1b2−a2b1=0x(b_1-b_2)-y(a_1-a_2)+a_1b_2-a_2b_1=0

The equation of the line passing through the distinct points (a1,b1)(a_1, b_1) and (a2,b2)(a_2, b_2) in slope-intercept form


y=b1−b2a1−a2x+a1b2−a2b1a1−a2,a1≠a2y=\dfrac{b_1-b_2}{a_1-a_2}x+\dfrac{a_1b_2-a_2b_1}{a_1-a_2}, a_1\not=a_2




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