Answer to Question #169117 in Analytic Geometry for william

Question

What is the vertex (h,k) given f= 2$\sqrt{x-2}$ +4?

Answer 1

For the given equation f = y = 2$\sqrt{\smash[b]{x-2}}$ +4 ,as per the above graph we can see that it is not a quadratic equation.

So vertex h and k are not available.

If the equation is f = y = (x-2)² +4

then h = 2 , k = 4