3x-3=3y-6 =z-7,find the unit vector parallel to the above line
1
Expert's answer
2020-08-06T17:42:50-0400
Let us rewrite the equation in form
31x−1=31y−2=1z−7 .
In such form the denominators represent the coordinates of the vector parallel to the line. The coordinates are (1/3, 1/3, 1). But we can see the vector is not unit, so we should normalize it.
The length of the vector above is
(1/3)2+(1/3)2+12=311.
Therefore, the unit vector will have coordinates (11/31/3,11/31/3,11/31) , after simplifying
Comments