a. (3+52,4+22)=(4,3)(\frac{3+5}{2},\frac{4+2}{2})=(4,3)(23+5,24+2)=(4,3)
b. (0+42,6+02)=(2,3)(\frac{0+4}{2},\frac{6+0}{2})=(2,3)(20+4,26+0)=(2,3)
c. (4+42,2−42)=(4,−1)(\frac{4+4}{2},\frac{2-4}{2})=(4,-1)(24+4,22−4)=(4,−1)
d. (−1−32,−5+42)=(−2,−12)(\frac{-1-3}{2},\frac{-5+4}{2})=(-2,-\frac{1}{2})(2−1−3,2−5+4)=(−2,−21)
e. (−3+82,2−22)=(52,0)(\frac{-3+8}{2},\frac{2-2}{2})=(\frac{5}{2},0)(2−3+8,22−2)=(25,0)
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